4x^2+244x+1496=0

Solution for 4x^2+244x+1496=0 equation:

4x^2+244x+1496=0

a = 4; b = 244; c = +1496;
Δ = b2-4ac
Δ = 2442-4·4·1496
Δ = 35600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35600}=\sqrt{400*89}=\sqrt{400}*\sqrt{89}=20\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(244)-20\sqrt{89}}{2*4}=\frac{-244-20\sqrt{89}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(244)+20\sqrt{89}}{2*4}=\frac{-244+20\sqrt{89}}{8}
$